Integrand size = 13, antiderivative size = 27 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2}{3} \sqrt {-1+x^3}+\frac {2}{9} \left (-1+x^3\right )^{3/2} \]
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Time = 0.01 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {272, 45} \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2}{9} \left (x^3-1\right )^{3/2}+\frac {2 \sqrt {x^3-1}}{3} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {x}{\sqrt {-1+x}} \, dx,x,x^3\right ) \\ & = \frac {1}{3} \text {Subst}\left (\int \left (\frac {1}{\sqrt {-1+x}}+\sqrt {-1+x}\right ) \, dx,x,x^3\right ) \\ & = \frac {2}{3} \sqrt {-1+x^3}+\frac {2}{9} \left (-1+x^3\right )^{3/2} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.67 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2}{9} \sqrt {-1+x^3} \left (2+x^3\right ) \]
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Time = 3.95 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.56
method | result | size |
risch | \(\frac {2 \left (x^{3}+2\right ) \sqrt {x^{3}-1}}{9}\) | \(15\) |
pseudoelliptic | \(\frac {2 \left (x^{3}+2\right ) \sqrt {x^{3}-1}}{9}\) | \(15\) |
trager | \(\left (\frac {2 x^{3}}{9}+\frac {4}{9}\right ) \sqrt {x^{3}-1}\) | \(16\) |
default | \(\frac {2 x^{3} \sqrt {x^{3}-1}}{9}+\frac {4 \sqrt {x^{3}-1}}{9}\) | \(23\) |
elliptic | \(\frac {2 x^{3} \sqrt {x^{3}-1}}{9}+\frac {4 \sqrt {x^{3}-1}}{9}\) | \(23\) |
gosper | \(\frac {2 \left (-1+x \right ) \left (x^{2}+x +1\right ) \left (x^{3}+2\right )}{9 \sqrt {x^{3}-1}}\) | \(24\) |
meijerg | \(\frac {\sqrt {-\operatorname {signum}\left (x^{3}-1\right )}\, \left (\frac {4 \sqrt {\pi }}{3}-\frac {\sqrt {\pi }\, \left (4 x^{3}+8\right ) \sqrt {-x^{3}+1}}{6}\right )}{3 \sqrt {\pi }\, \sqrt {\operatorname {signum}\left (x^{3}-1\right )}}\) | \(51\) |
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Time = 0.26 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.52 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2}{9} \, {\left (x^{3} + 2\right )} \sqrt {x^{3} - 1} \]
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Time = 0.09 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2 x^{3} \sqrt {x^{3} - 1}}{9} + \frac {4 \sqrt {x^{3} - 1}}{9} \]
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Time = 0.22 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.70 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2}{9} \, {\left (x^{3} - 1\right )}^{\frac {3}{2}} + \frac {2}{3} \, \sqrt {x^{3} - 1} \]
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Time = 0.28 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.70 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2}{9} \, {\left (x^{3} - 1\right )}^{\frac {3}{2}} + \frac {2}{3} \, \sqrt {x^{3} - 1} \]
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Time = 0.02 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.52 \[ \int \frac {x^5}{\sqrt {-1+x^3}} \, dx=\frac {2\,\sqrt {x^3-1}\,\left (x^3+2\right )}{9} \]
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